Mumbai Indians (MI) have won the Indian Premier League (IPL) title four times in last seven years and is the most successful team in the history of the tournament.
From Sachin Tendulkar to Jasprit Bumrah, some of the best Indian players and iconic overseas cricketers have played for MI in the last 12 years.
Bumrah, who was the Man of the Match award winner in the IPL 2019 final against Chennai Super Kings, after winning the tournament, has revealed his all-time Mumbai Indians XI which interestingly has only three foreign players.
In an interview with MITV, Bumrah picked Rohit Sharma and Sachin Tendulkar as the openers. Both of them have been highly successful as openers for the four-time IPL champions. Bumrah has made an interesting choice in the form of Ambati Rayudu at number three. Dinesh Karthik follows him at number four and is also the wicket-keeper of the team.
Hardik Pandya has been slated to bat at number five, followed by the West Indies’ giant Kieron Pollard. Both of them are among the cleanest strikers of the cricket ball, and have won quite a number of matches for MI on their own. Hardik’s elder brother Krunal comes in at number seven and is the third all-rounder in the team.
Among the bowlers, Bumrah picked Harbhajan Singh as the leading spinner of the team. Harbhajan had been a match-winner for Mumbai before he switched to Chennai. Sri Lankan fast bowler and the leading wicket taker in the history of IPL, Lasith Malinga, will lead the pace department.
In another interesting choice, Bumrah has opted for Australian fast bowler Mitchell Johnson at number 10. Johnson was hugely impressive for MI and played a key role in the team winning the 2013 and 2017 IPL finals. Also, Bumrah picked himself for the number 11 position.
— Mumbai Indians (@mipaltan) May 16, 2019
Jasprit Bumrah’s all-time MI XI:
Rohit Sharma, Sachin Tendulkar, Ambati Rayudu, Dinesh Karthik (wk), Hardik Pandya, Kieron Pollard, Krunal Pandya, Harbhajan Singh, Lasith Malinga, Mitchell Johnson, Jasprit Bumrah.